x^2+4x-496=0

Solution for x^2+4x-496=0 equation:

x^2+4x-496=0

a = 1; b = 4; c = -496;
Δ = b2-4ac
Δ = 42-4·1·(-496)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20\sqrt{5}}{2*1}=\frac{-4-20\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20\sqrt{5}}{2*1}=\frac{-4+20\sqrt{5}}{2}
$